Przejdź do treści

Superfactorial

🔗 Opis problemu

Implementacja

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
def superfactorial(n: int) -> int:
    result = factorial = 1

    for i in range(2, n + 1):
        factorial *= i
        result *= factorial

    return result

n = 4

result = superfactorial(n)

print(f"{n}$ = {result}")